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NiFe2O4-M金属陶瓷惰性阳极成分设计的热力学分析

Thermodynamic analysis for components design of NiFe2O4-M cermet inert anode

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【作者】 王宇栋王飚戴永年周晓奎张自华

【Author】 WANG Yu-dong,WANG Biao,DAI Yong-nian,ZHOU Xiao-kui,ZHANG Zi-hua(National Engineering Laboratory of Vacuum Metallurgy,Kunming University of Science and Technology,Kunming 650093,Yunnan Province,China)

【机构】 昆明理工大学真空冶金国家工程实验室

【摘要】 NiFe2O4-M金属陶瓷惰性阳极由氧化物陶瓷相和金属相组成。多数美国专利认为Fe,Ni,Cu,Co,Ti,Cr,Mn,Al,Pd,Ag,V,Zr,Y,La,Ta,Nb,Sc,Hf,Ca,Sn,Zn等21种金属均适合作为上述阳极的金属相成分。但文中的热力学详细分析计算结果表明:在上述前8种金属中,仅有Cu,Ni 2种适合作为惰性阳极的金属相;Al,Mn,Cr,Ti,Fe,Co不适合作为金属相成分,因为这些金属在阳极烧结过程中会对陶瓷相氧化物产生还原反应。除上述8种金属元素外,Pd,Ag,V,Zr,Y等其余13种金属,也因价格昂贵或资源短缺而不适宜作为上述阳极的金属相。

【Abstract】 NiFe2O4-M cermet inert anode is composed of the oxides ceramic and metallic phases.Most of U.S patents consider that 21 metals like Fe,Ni,Cu,Co,Ti,Cr,Mn,Al,Pd,Ag,V,Zr,Y,La,Ta,Nb,Sc,Hf,Ca,Sn,Zn,etc.are the constituents of the metallic phase suitable to the aforesaid anode.However,the results of thermodynamic analysis and computation show that only Cu and Ni are suitable to the metallic phase of the inert anode mentioned,and Al,Mn,Cr,Ti,Fe,Co are not suitable because they can reduce Fe2O3 or NiO in ceramic phase when being sintered.In addition,the surplus metals of 13 species,for example,Pd,Ag,V,Zr,Y,etc.are also not suitable due to high expense or poor resource.

【基金】 国家自然科学基金资助项目(50371033)
  • 【文献出处】 化学工程 ,Chemical Engineering(China) , 编辑部邮箱 ,2011年01期
  • 【分类号】TG148
  • 【被引频次】7
  • 【下载频次】122
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