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电站最小费用MATLAB优化仿真
MATLAB Optimized Simulation of Power Station Minimum Fees
【摘要】 通过详尽的分析,建立了两种切实可行的数学模型,并通过对这两种模型的分析比较最终得出最优方案,即利用拉格朗日算子法求有约函数的方法,达到实时调节各电站的出力,并且利用MATLAB强大的编程和计算能力对模型进行推广及其仿真。只须按程序要求输入n个电站的比例系数,便可求出各电站的装机容量和年最小费用。经计算,当n=2时,1#电站的装机容量为3.7536×106kw,2#电站的装机容量为0.9697×106kw,年最小运行总费用为2.1661×1014元。
【Abstract】 This paper builds two efficient mathematical models through detailed analysis for getting an optimal scheine.Namely,the Lagrange arithmetic operator method is used to do divisor function in order to adjust the power output of each power station at real time and spread the model and simulation using powerful MATLAB language.It only needs input the proportion coefficients of n power stations to get the capacity and minimum fee of each year.According to calculation:when n=2,the capacity of 1# power plant is 3.7536×106kW and the capacity of 2# power plant is 0.9697×106kW,and the minimum run fee of each year is 2.1661×1014 RMB.
【Key words】 Computer simulation; Mathematical model; Power station; Minimum fees;
- 【文献出处】 计算机仿真 ,Computer Simulation , 编辑部邮箱 ,2007年12期
- 【分类号】TP391.9
- 【被引频次】2
- 【下载频次】175