【摘要】 本文在25°至60℃温度范围内,测量了Na₃SbS₃·9H₂O、Na₂SbS₄·9H₂O水溶液的电导,指出这两种盐的水溶液均是强导电性的。由Nernst—Einstein方程D°=（RT/nF²）λ₀计算了在不同温度下,在稀水溶液中两种盐的扩散系数,并求出了扩散系数随温度变化的经验方程。最后讨论了在硫化碱溶液中Na₃SbS₃·9H₂O与NaOH的相互作用,指出Na₃SbS₃·9H₂O与NaOH按下述方程发生反应。Na₃SbS₃+4NaOH=NaSbO₂+3Na₂S+2H₂O更多还原

【Abstract】 The conductivity and diffusivity of sulphoantimonatic aqueous solution are studied in the range of temperature 25°—60℃.It indicated that the equivalent conductivity of Na₃SbS₃·9H₂O and Na₃SbS₄·9H₂O are 122Ω^-1·cm² and 123Ω^-1·cm² respectively at 25℃.According to the equation of Nernst--Einstein D°=（?）λ₀ the diffusivity of sulphoantimonate in dilute solution at different temperatures is calculated.The diffusivities of SbS₃^3- and SbS₄^3- ions in infi-nite dilute solution are obtained at 25℃.They are D（?）=0.64×10^-5cm²·sec^-1and D（?）=0.65×10^-5cm²·sec^-1 The relationship between the conductivity of Na₃SbS₃·9H₂O in sodium sulphide and that of sodium hydroxide solution is also studied.It is indicated that the reaction of Na₃SbS₃ with NaOH results in NaSbO₂ on the basis ofthe following equation:Na₃SbS₃+4NaOH=NaSbO₂+3Na₂S+2H₂O更多还原