【摘要】 Eu3+与不同分子量的聚二甲基硅氧烷(PDMS)形成的配合物PDMS-Eu(Ⅲ)受紫外光激发后,激发的PDMS将吸收的能量传递给Eu(Ⅲ),使Eu(Ⅲ)受到激发,因而使其在可见光区的发射荧光峰增强.由于PDMS-Eu(Ⅲ)中不同分子量的PDMS的构象不同,受光激发后的能量也不同,因此,含不同分子量PDMS配体的PDMS-Eu(Ⅲ)从PDMS到Eu(Ⅲ)的能量传递效率也不同,使Eu(Ⅲ)在可见光区的发射荧光峰峰强也不同.当PDMS的分子量为30 000时,PDMS-Eu(Ⅲ)的能量传递效率最高,可达48.2%,因而Eu(Ⅲ)在可见光区的发射荧光峰峰强最强.更多还原

【Abstract】 After PDMS-Eu(III) complexes formed from Eu3+ and PDMS is excited with ultraviolet light,the excited PDMS would transfer the absorption energy to Eu(Ⅲ), leading to the increase in the emission fluorescence peaks of Eu(Ⅲ) in the visible area.Because the conformations of PDMS-Eu(Ⅲ) complexes with PDMS of different molecular weights are different,their energies are different after the excitation of the light.Thus,their energy transfer efficiency from PDMS to Eu(Ⅲ) are different,leading to the different intensity of the emission fluorescence peaks of Eu(Ⅲ) in the visible area.When the molecular weight of PDMS is 30 000,the energy transfer efficiency of PDMS-Eu(Ⅲ) is the highest.It reaches 48.2%.Therefore,the intensity of the emission fluorescence peaks of Eu(Ⅲ) in the visible area is the highest.更多还原