【摘要】 用硝酸盐热分解法成功制备了BaZr(BO3)2:Eu(Eu3+的掺杂量为摩尔分数5%)荧光材料,并研究了其在254及147nm光束激发下的发光特性.254nm光束激发下的发射主峰位于612nm处,归属于Eu3+的5D0—7F2的电偶极跃迁,但在147nm光束激发下的发射主峰位于592nm处,归属于Eu3+的5D0—7F1的磁偶极跃迁.通过激发光谱分析,上述现象归因于在紫外激发下占据非对称格位Ba2+的Eu3+被优先激发,而在真空紫外激发下占据对称格位Zr4+的Eu3+被优先激发.结果表明BaZr(BO3)2:Eu并不适合作为等离子平板显示器用红色发光材料.更多还原

【Abstract】 BaZr（BO₃）₂:Eu phosphor was successfully prepared by thermal decomposition of the corresponding nitrates. The luminescence properties of BaZr（BO₃）₂:Eu were investigated under 254 and 147?nm excitation. In the emission spectrum of BaZr（BO₃）₂:Eu excited by 254?nm, the main peak is located at about 612?nm, which is due to the electric dipole transition of 5D₀—7F₂ of Eu 3+ . But in the emission spectrum excited by 147?nm, the main peak is located at about 592?nm, which is due to the magnetic dipole transition of 5D₀—7F₁ of Eu 3+ . Analysis of the excitation spectra indicated that Eu 3+ occupying the non-centrosymmetric site Ba 2+ can be excited preferentially by 254?nm light, but under 147?nm excitation, Eu 3+ occupying centrosymmetric site Zr 4+ can be excited preferentially. It shows that BaZr（BO₃）₂:Eu is not a suitable red phosphor for plasma display panel.更多还原