【摘要】 选择与腐殖酸有相似芳香结构的有机物进行氯化试验,测定其卤乙酸及三卤甲烷生成量,研究前体物化学结构与氯化消毒副产物生成特性的关系.结果表明:①主要卤乙酸生成活性排序为:对羟基苯甲酸>4-氨基苯乙酮>邻苯二酚>间苯二酚;主要三卤甲烷生成活性排序为:间苯二酚>4-氨基苯乙酮>2-羟基-4-氨基甲苯>对羟基苯甲酸.②卤乙酸的前期氯化反应速度排序为:间苯二酚>4-氨基苯乙酮>对羟基苯甲酸>邻苯二酚;三卤甲烷的前期氯化反应速度排序为:对羟基苯甲酸>2-羟基-4-氨基甲苯>间苯二酚>4-氨基苯乙酮.③对位或邻位取代基结构物质以生成卤乙酸为主;间位取代基结构物质以生成三卤甲烷为主.④苯环上羟基官能团生成消毒副产物的活性最高,酮基官能团次之;氨基官能团主要起到与其它活性官能团形成对位、邻位或间位结构的辅助作用;醛基和羧基官能团为惰性官能团;甲基官能团的作用有待深入考察.更多还原

【Abstract】 Some organic matter that have aromatic structure similar as humic acid are selected to conduct chlorination test,determined the formation of HAAs & THMs of tested matters,researched the relationship of the chemical structure of DBPFP with DBPs formation characteristics.The results indicated that: ①The sequence of HAAs formation activity is p-Hydroxybenzoic acid>p-Aminoacetophenone>o-Benzenediol>m-Benzenediol;and THMs’s is m-Benzenediol>p-Aminoacetophenone>2-Hydroxy-p-aminoacetophenone>p-Hydroxybenzoic acid.②The sequence of earlier chlorination reaction rate of HAAs is m-Benzenediol>p-Aminoacetophenone>p-Hydroxybenzoic acid>o-Benzenediol;and THMs’s is p-Hydroxybenzoic acid >2-Hydroxy-p-aminoacetophenone>m-Benzenediol>p-Aminoacetophenone.③The substances that having the substituent group structure of para & ortho position are mostly format HAAs,and one’s of having meta position are mostly format THMs.④ On the benzene ring,hydroxyl group has the highest activity of forming DBPs,and the second is ketone group;amino-group is play a part of auxiliary forming para,ortho or meta position structure mainly;aldehyde and carboxyl group are inert function group;the function of methyl group is remain to be determined.更多还原