【摘要】 研究了气态SnCl2 与O2 的高温氧化反应及与O2 、H2 O的高温氧化水解反应。表明 ,前者的反应产物为SnO2 和SnCl4 ,在 90 0℃和原始气相含O2 5 %时 ,反应进行得极为完全 ;后者的反应产物为SnO2 和HCl,在原始气相含水蒸汽及 1%的O2 时 ,只需温度达 80 0℃ ,SnCl2 即可被彻底氧化水解为SnO2 。可据此推断 ,在低锡物料氯化焙烧窑高温区 ,SnCl2 一经氯化形成进入气相 ,即被窑气中的O2 和H2 O ,氧化水解为SnO2 微粒并被窑气携带进入收尘系统。更多还原

【Abstract】 The oxidation reaction between gaseous SnCl 2 and O 2 and the oxidation or hydrolysis reaction between SnCl 2 and O 2 and H 2O at high temperature have been studied.The former reaction products are SnO 2 and SnCl 4 and the reaction goes perfectly at 900℃ and with the original O 2 concentration of 5%.The latter products are SnO 2 and HCl.SnCl 2 can be oxidized,hydrolyzed and turns completely into SnO 2 at the temperature less than up to 800℃ and with the original gas containing water vapor and 1%O 2.It can be referred from above results that SnCl 2,once formed by the chloridization reaction of low tin material in the higher temperature range of chloridization roaster and came into the roaster gas,will be oxidized and hydrolyzed by O 2 and H 2O in the roaster gas into SnO 2 particles that will be carried into the dust catching system by roaster gas.更多还原