【摘要】 采用固相反应法合成了具有硅钛钡石 (Ba2 TiSi2 O8)结构的化合物Sr2 TiSi2 O8,合成温度在12 50℃。对Sr2 TiSi2 O8的XRD衍射图进行指标化表明它属于四方晶系 ,晶胞系数为a =b =0 .83135nm ,c =0 .50 190nm ,α =β =γ =90°。Sr2 TiSi2 O8的粉末倍频信号强度约是KH2 PO4 (KDP)的 8倍。反射光谱显示其紫外吸收边为 2 70nm左右。利用自发成核法进行了Sr2 TiSi2 O8晶体生长研究。更多还原

【Abstract】 Sr 2TiSi 2O 8 with fresnoite type structure was synthesized by substituting Sr 2+ for Ba 2+ in Ba 2TiSi 2O 8 at 1250℃,the indexing result of the XRD pattern shows that Sr 2TiSi 2O 8 crystallizes in tetragon system with the lattice parameters a=b =0.83135nm, c =0.0190nm.The second harmonic generation (SHG) effect of Sr 2TiSi 2O 8 is about 8 times larger than that of KH 2PO 4(KDP).The ultraviolet absorption edge of Sr 2TiSi 2O 8 is around 270nm.Preliminary investigation of crystal growth was carried out by using the method of spontaneous nucleation.更多还原