【摘要】 用冶金热力学理论计算出 ＴｉＯ２－Ｈ３ＢＯ３-Ｎａ３ＡｌＦ６－Ａｌ－４．５Ｃｕ体系的起始反应温度，为９５０℃，并根据溶液热力学分析了 ＴｉＢ２颗粒形成的可能性当熔体中 ［Ｔｉ］、［Ｂ］的摩尔比为１／２时．在熔体中形成ＴｉＢ２颗粒；当熔体中［Ｔｉ］、［Ｂ］的摩尔比大于１／２时，熔体中除生成ＴｉＢ２颗粒外，还形成 ＴｉＡｌ３组织更多还原

【Abstract】 The reaction mechanism of forming Al-4.5Cu/TiB2 composite was studied and the starting reaction temperature among TiO2, H3BO3, Na3AIF6, Al-4.5Cu solution was calculated to be 950 t by means of thermodynamics for reaction synthesis of TiB2 particles. TiB2 particles should be formed when the mole ratio of [Ti] and [B] was equal to 1/2 in the melt. But another product was TiAl3 structure besides TiB2 particles when the mole ratio of [Ti] and [B] was over 1/2.更多还原