【摘要】 采用改进的Hummers法制得氧化石墨烯（GO）,与FeSO₄在120℃下回流还原,再通过浸渍Cu（NO₃）2、煅烧得到α-Fe₂O₃/Cu O/r GO非均相芬顿催化材料,并对材料进行扫描电子显微镜（SEM）表征和X射线粉末衍射（XRD）分析.以苯酚为目标污染物,研究α-Fe₂O₃/Cu O/r GO复合材料对苯酚的催化降解性能.结果表明:在p H=5.8,双氧水的初始浓度为40 mmol/L,催化剂投加量为1.0 g/L条件下,降解90 min时,α-Fe₂O₃/Cu O/r GO对0.1 g/L苯酚的去除率达到100%;在降解180 min时TOC的去除率约70%,说明α-Fe₂O₃/CuO/rGO对苯酚有较高的矿化效率,是一种具有应用前景的芬顿催化剂.更多还原

【Abstract】 The graphene oxide（ GO） was prepared with the modified Hummers method. Then it was reduced with FeSO₄·7 H₂ O through high temperature reflux. The reduction product was impregnated with Cu（ NO₃）₂ and calcined to obtain the heterogeneous Fenton catalytic material（ α-Fe₂O₃/CuO/r GO）. The materials were characterized with XRD and SEM. Phenol was used as the target pollutant to investigate the characteristics and efficiency ofα-Fe₂O₃/CuO/r GO for the phenol degradation. The experimental results showed that at the optimum state,p H =5.8,40 mmol/L H2 O2,1.0 g/L catalyst and 0.1 g/L Phenol,the degradation percentage of Phenol was 100%within 90 min; the TOC removal efficiency reached approximately 70% within 180 min. Therefore,α-Fe₂O₃/CuO/r GO showed high efficiency of phenol degradation and is a promising Fenton catalyst.更多还原