【摘要】 以亚甲基蓝和Fenton试剂为基础体系,考察木质纤维素典型酸解产物夺取羟基自由基的能力。选取香草醛、糠醛和葡萄糖为木质纤维素典型酸解模型化合物,重点考察了H₂O₂浓度、初始pH及Fe²⁺浓度等主要因素的影响,并通过高效液相色谱分析确认不同Fenton氧化程度下香草醛和糠醛的去除率。结果表明:香草醛、糠醛、葡萄糖均能与亚甲基蓝竞争羟基自由基,在等物质的量碳的条件下,夺取羟基自由基能力顺序为香草醛>糠醛>葡萄糖。在pH为3、Fe²⁺浓度为0.03mmol/L、H₂O₂浓度为0.12mmol/L条件下,分别加入香草醛和糠醛,去除率分别为67.08%和97.80%。进一步增大H₂O₂浓度为0.24mmol/L时,分别加入香草醛和糠醛,去除率分别为92.65%和100%;而同时加入香草醛和糠醛,香草醛去除率为82.76%,糠醛去除率为88.98%。该研究对促进生物质能产业发展具有重要现实意义。更多还原

【Abstract】 Based on the basic system of the methylene blue and Fenton reagent, the capability of the typical products from lignocellulose acidolysis to capture hydroxyl radicals（·OH） was investigated. In this paper, the vanillin, furfural and glucose were selected as the typical lignocellulose-related model compounds（LRMCs）. The main factors, such as H₂O₂ concentration, initial pH, and Fe²⁺ concentration, were investigated, and the removal efficiencies of LRMCs over different Fenton oxidation degrees were obtained by high performance liquid chromatography（HPLC）. The results showed that the vanillin, furfural, and glucose all could compete with methylene blue for hydroxyl radicals in the removal of LRMCs. Under the condition of equimolar carbon, the abilities to seize hydroxyl radicals were ranked as vanillin, furfural, and glucose, respectively. At the condition of pH of 3, Fe²⁺ concentration of 0.03 mmol/L, and H₂O₂ concentration of 0.12 mmol/L, the removal rates were 67.08% and 97.80%, when vanillin and furfural were added, respectively. While the concentration of H₂O₂ was increased to 0.24 mmol/L, the removal rates were 92.65% and 100%, respectively. Moreover, when the vanillin and furfural were added simultaneously, the removal rate of vanillin was 82.76%, and that of furfural was 88.98%. The research had an important and practical significance to promote the development of biomass energy industry.更多还原