【摘要】 目的:探讨常温环境人体运动中核心体温的预测方法,为预防运动型热损伤提供依据。方法:9名男性耐力性运动员在23℃、40%相对湿度的环境中进行递增负荷力竭自行车运动,起始负荷为100 W,增加20 W/10 min,维持60转/分;连续监控核心体温、心率、血乳酸。结果:核心体温升高值与心率(r=0.906)、血乳酸(r=0.835)正相关(均P<0.001)。核心体温升高值的预测模型:线性方程为:核心体温升高值=0.008×心率+0.00035×心率×血乳酸-0.670(R2=0.842,P<0.001);二次曲线方程为:核心体温升高值=0.221-0.007×心率+6.899×10-5×心率2(R2=0.827,P<0.001)。结论 :常温环境运动中人体的核心体温可应用心率和血乳酸进行预测。更多还原

【Abstract】 Objective: To explore a method of predicting core body temperature in a normal temperature environment in order to provide reference for preventing heat injury in exercise. Method: Nine male endurance athletes performed a load-incremental exercise to exhaustion on a cycle ergometer in a room with the temperature of 23℃ and the relative humidity of 40%. The exercise started with the load of 100 W, which was increased by 20 W every 10 min at a pedaling cadence of 60 rmp. During the experiment, the core body temperature, heart rate and blood lactic acid were monitored continuously. Result: The increased value of core body temperature correlates positively with heart rate(r=0.906) and blood lactic acid(r=0.835)(both P<0.001).The predictive model of the increased value of core body temperature is as follows :Linear equation: increased value of core body temperature=0.008 ×heart rate+0.00035 ×heart rate ×blood lactic acid-0.670(R2=0.842, P<0.001). Quadratic curve equation: increased value of core body temperature=0.221-0.007 ×heart rate +6.899 ×10-5×heart rate2(R2=0.827, P<0.001). Conclusion: In normal temperature environment,core body temperature can be predicted by heart rate and blood lactic acid during exercise.更多还原