【摘要】 以Ti N、RuCl3和H2IrCl6为原料,用真空浸渍-热分解法制备了RuO2-IrO2-Ti O2,研究了煅烧温度和n(Ru+Ir)∶n(Ti)对产物的影响。XRD分析表明:Ti N在高温煅烧时氧化生成金红石型Ti O2,RuO2、IrO2和Ti O2以固溶体的形式存在。CV、阳极极化曲线和EIS测试表明:RuO2-IrO2-Ti O2的最佳煅烧温度为400℃,随着n(Ru+Ir)∶n(Ti)的提高,催化剂的活性增强;在相同电位下,RuO2-IrO2-Ti O2的电流密度大于IrO2,可用作固体聚合物电解质(SPE)水电解催化剂。更多还原

【Abstract】 RuO2-IrO2-TiO2 was synthesized via vacuum impregnation-thermal decomposition method with TiN,RuCl2 and H2IrCl6 as raw materials,the effects of calcining temperature and n(Ru+Ir)∶n(Ti)on the products were studied.XRD analysis showed the TiN was oxidized to form rutile-type phase TiO2 by calcining at high temperature,RuO2,IrO2 and TiO2 existed in the form of solid solution.CV,anodic polarization curves and EIS tests showed the optimum calcining temperature of RuO2-IrO2-TiO2 was 400 ℃,the activity of the catalyst increased with the increasing of n(Ru+Ir)∶n(Ti).The current density of RuO2-IrO2-TiO2 based on the same potential was higher than IrO2,it could be used as catalyst of solid polymer electrolyte(SPE)water electrolysis.更多还原