【摘要】 使用分析纯试剂配料,在1500℃、保温1h的条件下得到了四元化合物20CaO·13Al2O3·3MgO·3SiO2(C20A13M3S3),研究了其氧化铝浸出性能,并通过XRD和SEM等分析了其在碳酸钠溶液中的作用机理。结果表明:C20A13M3S3具有一定的氧化铝浸出能力,其浸出率随着浸出时间的延长而提高,并在浸出2h后达到最大值68.87%,低于同条件下12CaO·7Al2O3的氧化铝浸出率(92.78%);C20A13M3S3和Na2CO3反应的主要产物为NaAl(OH)4和CaCO3,并含有少量的Ca2SiO4和Mg(OH)2;生成的Ca2SiO4具有较高的活性,浸出2h后,其分解率可达到19.35%。更多还原

【Abstract】 20CaO·13Al2O3·3MgO·3SiO2(C20A13M3S3) was obtained at 1 500 ℃ for 1h with analysis pure reagents proportioning.Alumina leaching property of C20A13M3S3 was studied.And the mechanism of the reaction between C20A13M3S3 and Na2CO3 solution was discussed by XRD and SEM method.The results indicate that alumina can be leached from C20A13M3S3.The leaching rate rises gradually with the prolongation of leaching time and reaches its maximum 68.87% after leaching for 2 h.The maximum leaching rate of C20A13M3S3 is lower than that of C12A7,which is 92.78% under the same condition.The main products of C20A13M3S3 reaction with Na2CO3 are NaAl(OH)4 and CaCO3,and a few amount of Ca2SiO4 and Mg(OH)2 are also generated.Ca2SiO4 generated from the reaction has high activity,and the decomposition rate can achieve 19.35% after leaching for 2h.更多还原