【摘要】 讨论了二阶四点边值问题:-x″(t)=f(t,x(t),x′(t)),t∈I=[0,1];x(0)=ax(ξ),x(1)=bx(η),其中0<ξ<η<1,0≤a,b≤1,f:[0,1]×[0,∞]→[0,∞]是连续的。利用拓扑度理论讨论了其多个解的存在性。更多还原

【Abstract】 The second-order four-point boundary value problem-x″(t)=f(t,x(t),x′(t)),t∈I=;x(0)=ax(ξ),x(1)=bx(η) was studied,where 0<ξ<η<1,0≤a,b≤1,and f: ×→ are non-negative continuous functions.Some degree theory arguments were used to get the multiplicity result.更多还原