【摘要】 设Ω={f(z):f(z)在|z|<1内解析,f(z)=z+∑+∞n=2anzn,an是实数,∑+∞n=2n|an|≤1}.该文找出了函数族Ω的极值点与支撑点.更多还原

【Abstract】 Let Ω=(f(z):f(z) is analytic in |z|<1 and f(z)=z+∑+∞n=2a -nz~n, a -n being real numbers, ∑+∞n=2 n|a -n|≤1). In this article the extreme points and support points of Ω are obtained.更多还原