【摘要】 在0.020mol.L-1HCl-4.0×10-4mol.L-1KI-1.6×10-5mol.L-1Mo(Ⅵ)介质中,罗丹明6G(RhG)在540nm处有1个荧光峰,在540nm处有1个同步荧光峰。当有H2O2存在时,H2O2与过量的I-反应生成I3-,I3-与RhG形成缔合微粒,在320,400,595nm处产生3个共振散射(RS)峰;而在540nm处荧光峰猝灭。H2O2浓度在0.068~34μg.mL-1范围内与400nm波长处的共振散射光强度呈线性关系。据此建立了一个测定水中H2O2的共振散射光谱分析法。光谱研究结果表明,(RhG-I3)n缔合微粒和界面的形成是导致体系RS增强和荧光猝灭的根本原因。更多还原

【Abstract】 Under the conditions of 0.02 mol·L^-1 HCl-4.0×10^-4 mol·L^-1 KI-1.6×10^-5 mol·L^-1 Mo（Ⅵ）, there is a fluorescence peak at 540 nm and a synchronous fluorescence peak at 540 nm for Rhodamine 6G （RhG）. When there exists H₂O₂, it reacts with I^- to form I^-₃. RhG and I^-₃ combine to form an ion association particle. The particles exhibit three resonance scattering peaks at 320 nm, 400 and 595 nm respectively. And there is fluorescence quenching at 540 nm. H₂O₂ concentration in the range of 0.068-34 μg·mL^-1 is proportional to the resonance scattering peak at 400 nm. And a new resonance scattering spectral method has been described for the determination of H₂O₂ in water samples. The spectral results have verified that the formation of （RhG-I₃）_n association particles and the interface are the main factor that causes the fluorescence quenching and resonance scattering effects.更多还原