【摘要】 采用权分担值的思想讨论了整函数关于微分多项式分担一个小函数的唯一性问题.主要证明了:设f,g是两个非常数整函数,n,m为正整数.fn(fm-1)f′,gn(gm-1)g′分担(1,2)且n>m+5,则f(z)≡g(z).该结论推广了已有的结果.更多还原

【Abstract】 Using the idea of weighted sharing,deal with the uniqueness problems on entire functions concerning differential polynomials.Mainly proved the following result:Let f,g be two nonconstant entire functions,n,m be positive integers.fⁿ(f^m-1)f′,gⁿ（g^m-1）g′ share（1,2） and n>m+5,then f（z）≡g（z）.Moreover,improve some former results.更多还原