【摘要】 场发射显示器 (fieldemissivedisplay ,FED)是一种新近发展起来的低压阴极射线平板显示器。Y2 SiO5∶Ce被筛选为这种显示器的蓝色荧光材料。然而该荧光粉发射光谱的峰值波长在 4 1 0nm ,处于人眼的不敏感区。由此提出 :如果通过调整材料的组成 ,使该荧光粉的发射波长向长波移动 ,这样对荧光粉本身的颜色和光效有何影响 ?进而对由该材料涂制的FED显示屏的总光效和显色性能有何影响 ?采用色度学模拟计算的方法回答上述问题 ;计算中 ,蓝粉的光谱用高斯函数模拟。结果表明 :发光峰带宽的增加和发光峰的红移都使蓝粉本身的光效提高 ;然而 ,为使FED同时具有高的光效和大的显色区域 ,蓝色荧光粉的发射峰最好位于 4 2 0～4 6 0nm之间 ,并且窄的发光峰对显示屏性能有利。这一结果实际上对其他彩色显示屏也是适用的更多还原

【Abstract】 Field emissive display (FED) is a newly developed flat panel display, the phosphors in which are excited by low voltage cathode rays. It is expected that this display would replace the widely used cathode ray tube (CRT) in near future. Y 2SiO 5∶Ce is the important candidate blue phosphor for FED. The emission peak of this phosphor is at 410 nm, an eye insensitive wavelength. Questions appear: should this emission peak be moved to longer wavelength to increase the brightness of this phosphor? If this is the case, how does this moving affect the efficiency and the color triangle area of FED device? Chromaticity simulation was tried to answer the questions. The emission spectrum of the blue phosphor was simulated by using Gaussian function. The luminous efficiencies and color coordinates of Y 2O 3∶Eu and Y 3Al 5O1 2∶Tb were selected for red and green phosphors. During the calculations, these parameters were kept constant. The color temperature and the brightness of the display were set as 6 500 K and 300 cd/m 2, respectively, while the voltage of the electron beams was chosen as 2 000 V. It is also assumed that the brightness of the phosphors linearly increases with the current density of the electron beams. When the emission peak position and width of the blue phosphor were varied, the color coordinates and brightness efficiency of the blue phosphor were calculated. Furthermore, the brightness efficiency and the color triangle area of the display were calculated. During the calculation, adjusting the current densities of the electron beams to maintain the color temperature and brightness of the display. The decrease of the current density indicates the increase of the efficiency. The simulation gives following results: (1) Increasing the peak wavelength and width enhances the luminous efficiency of the blue phosphor, but reduces the color saturation of it, but if the peak wavelength is kept shorter than 460 nm, the color saturation is acceptable for the display. (2) It is better to keep the peak wavelength of the blue phosphor in the range 420～460 nm, in which the phosphor possesses saturated blue color; the color triangle shows large area and the display performs high efficiency. (3) The wavelength of Y 2SiO 5∶Ce is too short for the display applications. If the wavelength could be shifted to longer wavelength, 20～40 nm, it would be beneficial to improve FED performance. In some extent, the results obtained in the present simulation are also suitable to other color displays.更多还原