【Abstract】 Cobalt(Ⅱ) can form complexes with Hdbm in different environments. Hdbm reacted with cobalt nitrate to give complex 1 [Co(dbm)2·2H2O]. When complex 1 reacted with pyridine, α stilbazole or 4,4′ bipyridine respectively, complex 2 [Co(DBM)2Py2] (Py=pyridine), 3 [Co(DBM)2Sbz2] (Sbz=α stilbazole) or 4 [Co(DBM)2BPy]n was obtained in turn through metathetical reaction. Thecoordination modes are octahedral polyhedrons. In the crystal structures, the two dbms take the plane position and two other donor molecules take the axial position. CCDC: 196070 for complex 2; 186859 for complex 3.更多还原