【摘要】 研究了铕(Ⅲ)和二苯甲酰甲烷(HDBM)形成的有机配体NaEu(DBM)4与聚丙烯酸(PPA)(Mr=5000)、聚(苯乙烯-丙烯酸)(PSAA)(Mr=3000)发生配位反应分别得到配合物Eu(Ⅲ)-DBM-PAA和NaEu(Ⅲ)-DBM-PSAA,得率分别为89.7％和87.3％。红外光谱、紫外光谱、X光电子能谱的测试表明了Eu3+分别与PAA,PSAA和DBM-发生配位。元素分析和电导率测定结果证明了一个Eu3+分别与PAA中二个链节或PSAA中三个链节的羧基和一个DBM-发生配位。Eu3+离子在配合物Eu(Ⅲ)-DBM-PAA和NaEu(Ⅲ)-DBM-PSAA中的质量分数分别为28.46％和12.23％。荧光光谱表明,常温下配合物在紫外光下发出强的红光,主要是Eu3+离子的5D0→7F2的能级跃迁。更多还原

【Abstract】 The metalorganic complex NaEu(DBM)4 is prepared by europium(Ⅲ) and Dibenzoyl Methane(HDBM). The coordination polymers Eu(Ⅲ)-DBM-PAA and NaEu(Ⅲ)-DBM-PSAA are synthesized by the reaction of NaEu(DBM)4 with polyacrylic acid(PAA) (Mr =5000)and copolymer of acrylic acid and styrene ( Mr = 3 000) (PSAA). The yield of Eu(Ⅲ)-DBM-PAA and NaEu(Ⅲ)-DBM-PSAA is about 89.7% and 87.3% , respectively. The results of FTIR, UV, XPS spectrum show that Eu3+ is coordinated with PAA, PSAA and DBM- respectively. The results of electric conductivity and elemental analysis indicate that each Eu3+ ion is coordinated by carboxyl from two units in the Eu(Ⅲ)-DBM-PAA molecule or three units in the NaEu(Ⅲ)-DBM-PSAA molecule and one DBM- . The Eu3+ content in coordination polymer Eu(Ⅲ)-DBM-PAA is 28.46% while it is 12.23% in NaEu(Ⅲ)-DBM-PSAA . The result of fluorescence spectroscopy shows that Eu-copolymer exhibited intense red light at 615 nm under UV excitation at room temperature, which is attributed to thesD0→7F2 transition of Eu3+ .更多还原