【摘要】 设m、n是正整数a1，a2，…，an是不同的奇数。本文证明了，当m＞1且n是2的方幂时Schur多项式f(x）=（x-a1）2m（x-a2)2m(x-an)2m+1在有理数域Q上是不可约的，该结果部分地解决了Schur猜想问题。更多还原

【Abstract】 Suppose m, n are positive integers, and a1, a2, ..,an are distinct odd numbers. it is proved, In this paper, that if m>1 and ms a power of 2, then the Schur polynomial f(x) =(x-a1 )2m(x-a,)2m.. (x-an)2m+ 1 is irreducible in the rational number range Q. so this result partly verifies a conjecture of I. Schur.更多还原