【摘要】 给定一个二阶曲线上相异６点．可组成６０个不同的此二阶曲线的内接六边形．即可得到６０条Ｐａｓｃａｌ线，它们中每４条交于一个Ｐａｓｃａｌ四线点，且每一条Ｐａｓｃａｌ线上都有３个Ｐａｓｃａｌ四线点。更多还原

【Abstract】 Given different 6 points on a curve of order 2, different 60 inscribed hexagon for the Curve of order 2 can be formed. That is .there are 60 Pascal lines in which every four imps can be intersected at the quadrilinear point, and there are three Pascal quadrilinear points on every Pascal line.更多还原