节点文献
不定同余方程x2n+(x+1)2n+…+(x+h)2n≡(x+h+1)2n(mod17)的解(Ⅰ)
The Solutions of Diophantine Congruence Equation x2n + (x + 1)2n+…+ (x+h)2n≡ (x+h + 1)2n (mod17) (I)
【摘要】 本文证明了:同余方程 x2n+(x+1)2n+…+(x+h)2n≡(x+h+1)2n(mod 17)有整数解的充分必要条件是 (1)若n≡1(mod 8),则h3,4,5,6,10,13(mod 17); (2)若n≡2(mod 8),则h3,4,8,9,1O,14(mod 17); (3)若n≡3(mod 8),则h6,10,11,(mod 17)。
【Abstract】 In this paper, we have proved that for the diophantinc congruence equationx2x+ (x+1)2n+…+(x+h)2n≡ (x+h+1)2n (mod 17)there arc integer solutions if and only if(1) when n=1 (mod8), then h3, 4, 5, 6, 10, 11, 13 (mod 17);(2) when n≡2 (mod8), then h3, 4, 8, 9, 10, 14 (mod 17);(3) when n≡3 (mod8), then h6, 10, 11 (mod 17).
【关键词】 模;
同余方程;
最小非负剩余;
Fermat定理;
【Key words】 module; congruence equation; minimal nonnegative residue; Fennat’s theorem;
【Key words】 module; congruence equation; minimal nonnegative residue; Fennat’s theorem;
- 【文献出处】 重庆交通学院学报 ,Journal of Chongqing Jiaotong University , 编辑部邮箱 ,1993年04期
- 【被引频次】3
- 【下载频次】30