【摘要】 通过对实验结果的分析.得出如下结论:在硫酸催化条件下,乳酸与乙醇酯化反应是一个对歧反应,其方程为-dc/dt=k_+c~2-K_-.其中k_+,k_-为酯化、水解速度常数.由此说明酯化反应为二级反应,水解反应为零级反应.更多还原

【Abstract】 The conclusion is obtained by analysing the experimental result. The reac- tion of esterification on lactic acid with ethanol is an opposing reaction H₂SO₄ is used for catalyst. Which kinetic equation may be written: -dr/dt= k₊c²-k_-,where k₊ and k_- are rate constants in the esterification and hydrolysis reactions, respectively, so that the esterification is second-order reaction, and the hydrolysis is zero-order reaction.更多还原