【摘要】 本文对白泥的可回收性进行了系统的研究、以便找出能使白泥可以回收的绿液极限含硅量。实验对SiO₂含量为9.26,4.91,3.51,1.19kg/m³的安验室绿液进行了白泥回收再用。实验结果表明,硅在白泥中的积累不是无限增加的。当循环次数足够大时,白泥中硅含量趋于衡定,并达到一个最大值“Am”。绿液中的硅含量越高,Am越大,Am=4.67e^0·27x（x是绿液中二氧化硅含量kg/m³,绿液总碱为100±9kg/m³Na₂O）。在任一循环次数n下的白泥中SiO₂含量由下式决定: y=Am(1-e^-n·3n),绿液中SiO₂含量每增加1kg/m³,白泥中的SiO₂含量将增加31％。当绿液中SiO₂含量高于2.82kg/m³时,Am>10％。这时回收灰中活性氧化钙小于80％,白泥回收效益不大。当绿液中SiO₂含量小于2.82kg/m³时,白泥的Am<10％。回收灰中活性氧化钙的含量高于80％,白泥回收价值较高。当绿液中SiO₂在2.82kg/m³左右时,白泥回收的效益取决于绿液和石灰的质量。白泥在回收煅烧时,除生成CaSiO₃以外,还会产生高钙比的硅化物,如:β-2CaO·SiO₂,白泥中SiO₂含量越高,β-2CaO·SiO₂的生成量越高。β-2CaO·SiO₂水化很慢,在苛化时不起反应。结果损失了大量的活性氧化钙。更多还原

【Abstract】 A systematic study had been made for the possibility of recovering limcmud contaminated with silicates. The purpose of the study was to find out the maximum allowable silica contents in green liquor which would not retard such recovering of limemud. The silica concentration of the green liquor used for investigation were 9.26, 4.91, 3.51, 1.19 kg/m³ （SiO₂）. It was found that accumulation of silica in the mud tended to approach a maximum （"AM"） and remain constant after a certain amount of repeated recycling involving caustcization limemud incineration and CaO recovering. The higher the silica content in the initial green liquor, the greater the value of "AM" in the limemud would be obtained. With AM=4.67·e^0·27x （where x is the silica content in kg/m³ （SiO₂） of the green liquor） and total alkali of the green liquor in the range of 100±9 Na₂O kg/m³, the percentage of silica in the mud in any cycle number "n" could be expressed as Y=AM(1-e^-0·3n), where Y is silica percentage in the mud. With an increment of 1 kg/m³ （SiO₂） in the green liquor 31%（SiO₂） increment would be found in the mud. When the silica concentration in the green liquor happened to be higher than 2.82 kg/m³ （SiO₂）, AM 10% and the CaO in the lime recovered less than 80%, the limemud ought to be considered worthless for further treatment, when the silica concentration was less then 2.82, AM<10% and the CaO more then 80%, the limemud could be worth reusing. When the silica concentration was equal to 2.82, the purity of the green liquor and the lime would be the domininating factors for limemud recovery. In the reburning of the limemud, silica tended to form CaSiO₃ and compounds, such as β-2CaO·SiO₂. The higher the silica contents in the mud, the more β-2CaO·SiO₂, would be formed. β-2CaO. SiO₂ would hydrate very slowly. This did not take place in the recausticization reaction, which instead, brought about high active CaO losses.更多还原