【摘要】 本文主要证明了下述结论: 定理设f（z）是整函数,其下级μ（f）<,若f（z）仅有有穷条julia方向,则f（z）的Nevanlinna亏量在坐标平移下不变,即任取a∈C,z₀∈C,均有δ(a,f（z）=δ（a,f（z+z₀））.更多还原

【Abstract】 The following conclusions have been proved in the paper. Theorem: Let f (z) be an entire function, with lower order μ(f)<∞, and f (z) has only finite Julias directions. Then the deficiencies of f (z) is independent of the choice of the origin.更多还原