【摘要】 Tb³⁺离子激活的Me₂SiO₄（Me=Ca、Sr、Ba）发光材料是用分析纯试剂合成并加以提纯的BaCO₃、SrCO₃、CaCO₃、H₂SiO₃、Li₂CO₃和Tb₂（C₂O₄）₃为原料,通过固态反应的合成方法而制成的。由X-光衔射谱,确定了样品的结构。通过荧光测量,探讨了Tb³⁺离子在碱土金属正硅酸盐中的发光行为。更多还原

【Abstract】 In this paper the synthesis method of Me2SiO4:Tb3+ (Me = Ca, Sr, Ba) is reported. The Me2SiO4:Tb3+ (Me = Ca, Sr, Ba) were fired at 950℃ for two hours using MeCO3, H2SiO3, Li2O3 and Tb2(C2O4)3 with suitable mole ratio, reground, and then retired in air at 1250℃ for three hours. Li+ ions were added to compensate charges. The crystalline phase was checked by a X-ray powder diffractometer. The excitation and emission spectra were measured by MPF- 4 fluorospectrometer.The emission spectra of Me2SjO4:Tb3+ (Me = Ca, Sr, Ba) under UV excitation originate from 5D3-7FI and 5D4-7FJ transitions of Tb3+ ion. The strongest peak corresponds to the transition of 5D4-7F5, when the concentration of Tb3+ ion is 0.05-0.3mol. The difference between emission spectra of Me2SiO4:Tb3+ (Me = Ca, Sr, Ba) is small. The concentration quenching of the luminescence of Me2SiO4:Tb3+ is discussed. It is found that the variation in intensities of 5D4-7F5 and 5D3-7F5 transitions with the terbium concentration is of different trends. The optimum concentration of Tb3+ ion for Ca2SiO4:Tb3+ or Sr2SiO4:Tb3+ is about 0.l5mol., and that of Ba2SiO4:Tb3+ is about 0.25mol.It is well known that the relationship between the luminescence intensity I and the concentration of activator x can be written as I/x = A(1 + βθ/3)-1, where θ is a constant related to the interaction between activator ions, A and β are two parameters. We have found that 6 is equal to three for the transition of 5D4-7F5 and 6 for the transition of 5D3-7F5. This result means that the concentration quenching mechanism for 5D4-7F5 and 5D3-7F5 is different.更多还原