【摘要】 本文用两相滴定法测定了HDEHP在煤油/H₂O体系中的二聚常数（K₂）和两相电离常数（（K_d）/（K_a））位,其结果（25±0.5℃）为: 其中[],（）分别表示浓度和活度, （o） 代表有机相,水相不加下标。在上述实验的基础上,考察了HDEP—煤油/0.1M（N_a,H）Cl体系萃钠的行为。在不直接取样分析两相纳含量的情况下,通过对两相滴定数据的数学处理,表明: 当α（体系中HDEHP被NaOH中和的分数）较低时,萃取反应为当α>25%且有机相HDEHP的初始浓度C₍HA（0）=1×10^-3M时,萃钠的反应为1g K_1,0^Na=-6.70±0.04更多还原

【Abstract】 A two-phase titration method has been used in the determination of K₂ and （K_d）/（K_o） of HDEHP （or HA）in kerosene-water system at 25±0.5℃.Its results are as follows:Where [ ]（0） and [ ] stand for the equilibrium concentration of HDEHP in organic phase and those of species in aqueous please respectively. And pH=-Lg （H⁺）.The extraction of Na⁺ with HDEHP in kerosene from 0.1M sodium chloride solution has been also investigated with titration. In this experiment, we can calculate the extraction constants conveniently from the pH of equilibrium aqueous phase and the volume of titrant （in this case, standard NaOH ） ueed. The experimental results show: when the percentage of HDEHP neutralized by sodium hydroxide"a" is less than 2%, the extraction reaction can be expresed by the following equation:while q>25%, the equation is更多还原